1. Regular Expression Matching
Implement regular expression matching with support for'.'
and'*'
.
'.' Matches any single character.
'*' Matches zero or more of the preceding element.
public class Solution {
public boolean isMatch(String s, String p) {
int m = s.length();
int n = p.length();
boolean[][] dp = new boolean[m + 1][n + 1];
dp[0][0] = true;
for(int i = 1; i <= n; i ++) {
if(p.charAt(i - 1) == '*')
dp[0][i] = dp[0][i - 2];
}
for(int i = 1; i <= m; i ++) {
for(int j = 1; j <= n; j ++) {
if(s.charAt(i - 1) == p.charAt(j - 1) || p.charAt(j - 1) == '.')
dp[i][j] = dp[i - 1][j - 1];
else if(p.charAt(j - 1) == '*') {
dp[i][j] = dp[i][j - 2];
if(s.charAt(i - 1) == p.charAt(j - 2) || p.charAt(j - 2) == '.')
dp[i][j] = dp[i][j] || dp[i - 1][j];
}
}
}
return dp[m][n];
}
}
2. Wildcard Matching
Implement wildcard pattern matching with support for'?'
and'*'
.
'?' Matches any single character.
'*' Matches any sequence of characters (including the empty sequence, may contain different character).
public class Solution {
public boolean isMatch(String s, String p) {
int m = s.length();
int n = p.length();
boolean[][] dp = new boolean[m + 1][n + 1];
dp[0][0] = true;
for(int i = 1; i <= n; i ++) {
dp[0][i] = (p.charAt(i - 1) == '*') && dp[0][i-1];
}
for(int i = 1; i <= m; i ++) {
for(int j = 1; j <= n; j ++) {
if(s.charAt(i - 1) == p.charAt(j - 1) || p.charAt(j - 1) == '?')
dp[i][j] = dp[i - 1][j - 1];
else if(p.charAt(j - 1) == '*') {
dp[i][j] = dp[i][j - 1] || dp[i - 1][j];
}
}
}
return dp[m][n];
}
}